add examples from the power of prolog
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src/prolog/examples/expert_system.pl
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src/prolog/examples/expert_system.pl
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:- use_module(library(dcgs)).
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:- use_module(library(reif)).
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animals([animal(dog, [is_true('has fur'), is_true('says woof')]),
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animal(cat, [is_true('has fur'), is_true('says meow')]),
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animal(duck, [is_true('has feathers'), is_true('says quack')])]).
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animal(A) :-
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animals(Animals),
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Known0 = [],
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phrase(any_animal(Animals, A), [Known0], _).
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any_animal([Animal|Animals], A) -->
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any_animal_(Animal, Animals, A).
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any_animal_(animal(A0, []), Animals, A) -->
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( { A0 = A }
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; any_animal(Animals, A)
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).
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any_animal_(animal(A0, [C|Cs]), Animals, A) -->
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state0_state(Known0, Known),
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{ condition_truth(C, T, Known0, Known) },
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next_animal(T, animal(A0,Cs), Animals, A).
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next_animal(yes, Animal, Animals, A) --> any_animal([Animal|Animals], A).
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next_animal(no, _, Animals, A) --> any_animal(Animals, A).
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state0_state(S0, S), [S] --> [S0].
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condition_truth(is_true(Q), Answer, Known0, Known) :-
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if_(known_(Q,Answer,Known0),
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Known0 = Known,
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( writeq([Q, ?]), nl,
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read(Answer),
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Known = [known(Q,Answer)|Known0])).
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known_(What, Answer, Known, Truth) :-
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if_(memberd_t(known(What,yes), Known),
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( Answer = yes, Truth = true ),
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if_(memberd_t(known(What,no), Known),
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( Answer = no, Truth = true),
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Truth = false)).
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54
src/prolog/examples/plres.pl
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src/prolog/examples/plres.pl
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/* - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
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Written by Markus Triska, triska@metalevel.at, Sept. 5th 2006
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Public domain code.
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----------------------------------------------------------------------
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Resolution calculus for propositional logic.
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For more information about theorem proving with Prolog, see:
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https://www.metalevel.at/prolog/theoremproving
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==============================================
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Input is a formula in conjunctive normal form, represented as a
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list of clauses; clauses are lists of atoms and terms not/1.
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Example:
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?- Clauses = [[p,not(q)], [not(p),not(s)], [s,not(q)], [q]],
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pl_resolution(Clauses, Rs),
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maplist(portray_clause, Rs).
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%@ [p, not(q)]-[not(p), not(s)] -->
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%@ [not(q), not(s)].
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%@ [s, not(q)]-[not(q), not(s)] -->
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%@ [not(q)].
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%@ [q]-[not(q)] -->
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%@ [].
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Iterative deepening is used to find a shortest refutation.
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- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - */
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:- use_module(library(dcgs)).
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:- use_module(library(dif)).
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:- use_module(library(lists)).
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pl_resolution(Clauses0, Chain) :-
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maplist(sort, Clauses0, Clauses), % remove duplicates
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length(Chain, _),
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pl_derive_empty_clause(Chain, Clauses).
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pl_derive_empty_clause([], Clauses) :-
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member([], Clauses).
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pl_derive_empty_clause([C|Cs], Clauses) :-
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pl_resolvent(C, Clauses, Rs),
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pl_derive_empty_clause(Cs, [Rs|Clauses]).
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pl_resolvent(((As0-Bs0) --> Rs), Clauses, Rs) :-
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member(As0, Clauses),
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member(Bs0, Clauses),
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select(Q, As0, As),
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select(not(Q), Bs0, Bs),
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append(As, Bs, Rs0),
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sort(Rs0, Rs), % remove duplicates
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maplist(dif(Rs), Clauses).
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